What are the solutions to the equation (y+150)^2=50 ?

The solutions to the equation (y+150)^2=50 are y=5sqrt(2)-150,y=-5sqrt(2)-150

Find the zeros of (y+150)^2=50

The zeros of (y+150)^2=50 are y=5sqrt(2)-150,y=-5sqrt(2)-150

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(y + 150)^{2} = 50

y = 52 - 150, y = - 52 - 150

Decimal Notation

y = - 142.92893 \dots, y = - 157.07106 \dots

Solution steps

(y + 150)^{2} = 50

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 150 = 50 : y = 52 - 150

Solve

y + 150 = - 50 : y = - 52 - 150

The solutions to the quadratic equation are:

y = 52 - 150, y = - 52 - 150

3.2 (\frac{1}{2}) - 2.5 (\frac{3}{5}) + 1.4 (\frac{2}{7})

3 m (m + 5) = 0

(- 216)^{\frac{1}{3}}

0 = - 0.0008 x + 7.2

5 (4 u + 7) \geq 20 u + 33

What are the solutions to the equation (y+150)^2=50 ?
The solutions to the equation (y+150)^2=50 are y=5sqrt(2)-150,y=-5sqrt(2)-150
Find the zeros of (y+150)^2=50
The zeros of (y+150)^2=50 are y=5sqrt(2)-150,y=-5sqrt(2)-150