What is expand (f\circ 2x^2+1)(x+1) ?

The solution to expand (f\circ 2x^2+1)(x+1) is 2\circ fx^3+2\circ fx^2+x+1

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expand (f\circ 2x^2+1)(x+1)

expand

(f \circ 2 x^{2} + 1) (x + 1)

2 \circ f x^{3} + 2 \circ f x^{2} + x + 1

Solution steps

(f \circ 2 x^{2} + 1) (x + 1)

= (2 \circ f x^{2} + 1) (x + 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = f \circ 2 x^{2}, b = 1, c = x, d = 1

= f \circ 2 x^{2} x + f \circ 2 x^{2} \cdot 1 + 1 \cdot x + 1 \cdot 1

= 2 \circ f x^{2} x + 2 \cdot 1 \circ f x^{2} + 1 \cdot x + 1 \cdot 1

Simplify

2 \circ f x^{2} x + 2 \cdot 1 \circ f x^{2} + 1 \cdot x + 1 \cdot 1 : 2 \circ f x^{3} + 2 \circ f x^{2} + x + 1

= 2 \circ f x^{3} + 2 \circ f x^{2} + x + 1

e^{4 x} \cdot (38 - 7 x)

- 2 (y + x \frac{d y}{d x})

y e^{x} (x + y)

(1, - 1, - 1) ((- 1, 1, - 1) x (- 1, - 1, 1))

(3 x + vx) (v d x + x d v)

What is expand (f\circ 2x^2+1)(x+1) ?
The solution to expand (f\circ 2x^2+1)(x+1) is 2\circ fx^3+2\circ fx^2+x+1