What is expand Q_{0}(1-e^{-y/a}) ?

The solution to expand Q_{0}(1-e^{-y/a}) is Q_{0}-e^{-y/a}Q_{0}

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expand Q_{0}(1-e^{-y/a})

expand

Q_{0} (1 - e^{- \frac{y}{a}})

Q_{0} - e^{- \frac{y}{a}} Q_{0}

Solution steps

Q_{0} (1 - e^{- \frac{y}{a}})

Apply the distributive law:

a (b - c) = ab - a c

a = Q_{0}, b = 1, c = e^{- \frac{y}{a}}

= Q_{0} \cdot 1 - Q_{0} e^{- \frac{y}{a}}

= 1 \cdot Q_{0} - e^{- \frac{y}{a}} Q_{0}

Multiply:

1 \cdot Q_{0} = Q_{0}

= Q_{0} - e^{- \frac{y}{a}} Q_{0}

\frac{( x + 1 ) ( x - 4 )}{x - 1}

\frac{9 - 4 y}{4}

\frac{3 x + 1}{x ( 9 - x )}

2 (1 - e^{- x})

2 c (4 - e)

What is expand Q_{0}(1-e^{-y/a}) ?
The solution to expand Q_{0}(1-e^{-y/a}) is Q_{0}-e^{-y/a}Q_{0}