What is expand (4x^2-4x+2)/((2x-1)^2) ?

The solution to expand (4x^2-4x+2)/((2x-1)^2) is (4x^2-4x+2)/(4x^2-4x+1)

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expand (4x^2-4x+2)/((2x-1)^2)

expand

\frac{4 x ^{2} - 4 x + 2}{( 2 x - 1 ) ^{2}}

\frac{4 x ^{2} - 4 x + 2}{4 x ^{2} - 4 x + 1}

Solution steps

\frac{4 x ^{2} - 4 x + 2}{( 2 x - 1 ) ^{2}}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 2}{4 x ^{2} - 4 x + 1}

\frac{( x + 5 ) ( 5 x + 10 )}{( x - 5 ) ^{2}}

4 w^{9 (7 w^{2} + 2 w)}

(36 - 9 x = x - 4) \cdot 20

(1 - x) y^{'} (x) + y^{2}

e^{x} (y + y^{2} x e^{- x})

What is expand (4x^2-4x+2)/((2x-1)^2) ?
The solution to expand (4x^2-4x+2)/((2x-1)^2) is (4x^2-4x+2)/(4x^2-4x+1)