What is expand ((x^2-4x+13)(2x+1))/2 ?

The solution to expand ((x^2-4x+13)(2x+1))/2 is x^3-(7x^2)/2+11x+13/2

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expand ((x^2-4x+13)(2x+1))/2

expand

\frac{( x ^{2} - 4 x + 13 ) ( 2 x + 1 )}{2}

x^{3} - \frac{7 x ^{2}}{2} + 11 x + \frac{13}{2}

Solution steps

\frac{( x ^{2} - 4 x + 13 ) ( 2 x + 1 )}{2}

Expand

(x^{2} - 4 x + 13) (2 x + 1) : 2 x^{3} - 7 x^{2} + 22 x + 13

= \frac{2 x ^{3} - 7 x ^{2} + 22 x + 13}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{3} - 7 x ^{2} + 22 x + 13}{2} = \frac{2 x ^{3}}{2} - \frac{7 x ^{2}}{2} + \frac{22 x}{2} + \frac{13}{2}

= \frac{2 x ^{3}}{2} - \frac{7 x ^{2}}{2} + \frac{22 x}{2} + \frac{13}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{3} - \frac{7 x ^{2}}{2} + \frac{22 x}{2} + \frac{13}{2}

Divide the numbers:

\frac{22}{2} = 11

= x^{3} - \frac{7 x ^{2}}{2} + 11 x + \frac{13}{2}

69 x - 11 y - 21 z - 45 x

(e^{x} \cdot y + 1) d x - (e^{x} - 1) d y

(- 3 - i)^{7}

\frac{n ^{2} ( n ^{2} + 1 )}{2}

\frac{x ^{2} - 25 y}{5 ( 5 x + 25 y )}

What is expand ((x^2-4x+13)(2x+1))/2 ?
The solution to expand ((x^2-4x+13)(2x+1))/2 is x^3-(7x^2)/2+11x+13/2