What is expand ((t^2+3)^2)/(t^6) ?

The solution to expand ((t^2+3)^2)/(t^6) is 1/(t^2)+6/(t^4)+9/(t^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((t^2+3)^2)/(t^6)

expand

\frac{( t ^{2} + 3 ) ^{2}}{t ^{6}}

\frac{1}{t ^{2}} + \frac{6}{t ^{4}} + \frac{9}{t ^{6}}

Solution steps

\frac{( t ^{2} + 3 ) ^{2}}{t ^{6}}

(t^{2} + 3)^{2} = t^{4} + 6 t^{2} + 9

= \frac{t ^{4} + 6 t ^{2} + 9}{t ^{6}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t ^{4} + 6 t ^{2} + 9}{t ^{6}} = \frac{t ^{4}}{t ^{6}} + \frac{6 t ^{2}}{t ^{6}} + \frac{9}{t ^{6}}

= \frac{t ^{4}}{t ^{6}} + \frac{6 t ^{2}}{t ^{6}} + \frac{9}{t ^{6}}

Cancel

\frac{t ^{4}}{t ^{6}} : \frac{1}{t ^{2}}

= \frac{1}{t ^{2}} + \frac{6 t ^{2}}{t ^{6}} + \frac{9}{t ^{6}}

Cancel

\frac{6 t ^{2}}{t ^{6}} : \frac{6}{t ^{4}}

= \frac{1}{t ^{2}} + \frac{6}{t ^{4}} + \frac{9}{t ^{6}}

\frac{1}{x ( 1800 - x )}

sin (x (1 + csc (x)) - sin (x))

(w + x + y + z + 1)^{3}

\frac{x ( x - 5 )}{2}

\frac{x ^{2} + 5}{x ( x - 4 ) ( x - 5 )}

What is expand ((t^2+3)^2)/(t^6) ?
The solution to expand ((t^2+3)^2)/(t^6) is 1/(t^2)+6/(t^4)+9/(t^6)