What is expand ((x+1)^2)/(3x^4) ?

The solution to expand ((x+1)^2)/(3x^4) is 1/(3x^2)+2/(3x^3)+1/(3x^4)

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expand ((x+1)^2)/(3x^4)

expand

\frac{( x + 1 ) ^{2}}{3 x ^{4}}

\frac{1}{3 x ^{2}} + \frac{2}{3 x ^{3}} + \frac{1}{3 x ^{4}}

Solution steps

\frac{( x + 1 ) ^{2}}{3 x ^{4}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{x ^{2} + 2 x + 1}{3 x ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 2 x + 1}{3 x ^{4}} = \frac{x ^{2}}{3 x ^{4}} + \frac{2 x}{3 x ^{4}} + \frac{1}{3 x ^{4}}

= \frac{x ^{2}}{3 x ^{4}} + \frac{2 x}{3 x ^{4}} + \frac{1}{3 x ^{4}}

Cancel

\frac{x ^{2}}{3 x ^{4}} : \frac{1}{3 x ^{2}}

= \frac{1}{3 x ^{2}} + \frac{2 x}{3 x ^{4}} + \frac{1}{3 x ^{4}}

Cancel

\frac{2 x}{3 x ^{4}} : \frac{2}{3 x ^{3}}

= \frac{1}{3 x ^{2}} + \frac{2}{3 x ^{3}} + \frac{1}{3 x ^{4}}

\frac{63}{( x + 8 ) x}

\frac{4 x}{( - x + 1 ) ( x + 1 )}

\frac{3 x - 5}{( x - 3 ) ( x ^{2} - 3 x + 2 )}

(- 3, 4, 2) (2 x - 4 y + z - 7)

A (- 1, 3) B (5, - 2)

What is expand ((x+1)^2)/(3x^4) ?
The solution to expand ((x+1)^2)/(3x^4) is 1/(3x^2)+2/(3x^3)+1/(3x^4)