What is expand-(6e^{-st}(2+t))/(s^3) ?

The solution to expand-(6e^{-st}(2+t))/(s^3) is -(12e^{-st})/(s^3)-(6e^{-st}t)/(s^3)

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expand-(6e^{-st}(2+t))/(s^3)

expand

- \frac{6 e ^{- s t} ( 2 + t )}{s ^{3}}

- \frac{12 e ^{- s t}}{s ^{3}} - \frac{6 e ^{- s t} t}{s ^{3}}

Solution steps

- \frac{6 e ^{- s t} ( 2 + t )}{s ^{3}}

Expand

6 e^{- s t} (2 + t) : 12 e^{- s t} + 6 e^{- s t} t

= - \frac{6 e ^{- s t} t + 12 e ^{- s t}}{s ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 e ^{- s t} + 6 e ^{- s t} t}{s ^{3}} = - (\frac{12 e ^{- s t}}{s ^{3}}) - (\frac{6 e ^{- s t} t}{s ^{3}})

= - (\frac{12 e ^{- s t}}{s ^{3}}) - (\frac{6 e ^{- s t} t}{s ^{3}})

Remove parentheses:

(a) = a

= - \frac{12 e ^{- s t}}{s ^{3}} - \frac{6 e ^{- s t} t}{s ^{3}}

\frac{s}{( s ^{2} + 3 ) ^{2}}

d x [(x + 1) (x + 3)]

f (\frac{1}{2}, - 1)

\frac{x}{( x - 1 ) ( - 2 x + 1 )}

\frac{x - 5 ( 3 + x + 4 )}{- x + 5}

What is expand-(6e^{-st}(2+t))/(s^3) ?
The solution to expand-(6e^{-st}(2+t))/(s^3) is -(12e^{-st})/(s^3)-(6e^{-st}t)/(s^3)