What is expand (2x+2(3+a)^2)/(y-1) ?

The solution to expand (2x+2(3+a)^2)/(y-1) is (2x+18+12a+2a^2)/(y-1)

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expand (2x+2(3+a)^2)/(y-1)

expand

\frac{2 x + 2 ( 3 + a ) ^{2}}{y - 1}

\frac{2 x + 18 + 12 a + 2 a ^{2}}{y - 1}

Solution steps

\frac{2 x + 2 ( 3 + a ) ^{2}}{y - 1}

(3 + a)^{2} = 9 + 6 a + a^{2}

= \frac{2 x + 2 ( a ^{2} + 6 a + 9 )}{y - 1}

Expand

2 x + 2 (9 + 6 a + a^{2}) : 2 x + 18 + 12 a + 2 a^{2}

= \frac{2 x + 18 + 12 a + 2 a ^{2}}{y - 1}

d y (2 a x + b) d x

- (- 5)^{2}

4 (x - 8 = 40)

(y^{2} - v^{2} y^{2}) (v d y + y d v)

1 7^{(k + 1)} - 9^{(k + 1)}

What is expand (2x+2(3+a)^2)/(y-1) ?
The solution to expand (2x+2(3+a)^2)/(y-1) is (2x+18+12a+2a^2)/(y-1)