What is expand (x(x+1)(x-1))/3 ?

The solution to expand (x(x+1)(x-1))/3 is (x^3)/3-x/3

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expand (x(x+1)(x-1))/3

expand

\frac{x ( x + 1 ) ( x - 1 )}{3}

\frac{x ^{3}}{3} - \frac{x}{3}

Solution steps

\frac{x ( x + 1 ) ( x - 1 )}{3}

Expand

x (x + 1) (x - 1) : x^{3} - x

= \frac{x ^{3} - x}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - x}{3} = \frac{x ^{3}}{3} - \frac{x}{3}

= \frac{x ^{3}}{3} - \frac{x}{3}

(2 e - 9)^{2}

9 (a + h) + 12

\frac{( 4 + x )}{( ( 1 - x ) ( 4 + x ^{2} ) )}

\frac{( 1 - 2 s )}{( 4 s + 1 ) ( s + 1 ) s}

\frac{1 + x ^{2} + x}{x ( x - 1 )}

What is expand (x(x+1)(x-1))/3 ?
The solution to expand (x(x+1)(x-1))/3 is (x^3)/3-x/3