What is expand ((b-a)^2)/n ?

The solution to expand ((b-a)^2)/n is (b^2)/n-(2ab)/n+(a^2)/n

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expand ((b-a)^2)/n

expand

\frac{( b - a ) ^{2}}{n}

\frac{b ^{2}}{n} - \frac{2 ab}{n} + \frac{a ^{2}}{n}

Solution steps

\frac{( b - a ) ^{2}}{n}

(b - a)^{2} = b^{2} - 2 ab + a^{2}

= \frac{b ^{2} - 2 ab + a ^{2}}{n}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{b ^{2} - 2 ba + a ^{2}}{n} = \frac{b ^{2}}{n} - \frac{2 ba}{n} + \frac{a ^{2}}{n}

= \frac{b ^{2}}{n} - \frac{2 ab}{n} + \frac{a ^{2}}{n}

\frac{s + 6}{( s ^{2} + s + c ) ( s + 4 )}

(y^{2} - 4 y + 9) - (3 y^{2} - 6 y = 9)

\frac{- 3 ( x + h ) ^{2} + 3 ( x + h ) - 4}{h}

\frac{k ^{a}}{n ( k ^{a} - n ^{a} )}

\frac{1}{( w i + 0.5 ) ^{2}}

What is expand ((b-a)^2)/n ?
The solution to expand ((b-a)^2)/n is (b^2)/n-(2ab)/n+(a^2)/n