What is expand 1/((y+2)(y-5)(y+7)) ?

The solution to expand 1/((y+2)(y-5)(y+7)) is 1/(y^3+4y^2-31y-70)

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expand 1/((y+2)(y-5)(y+7))

expand

\frac{1}{( y + 2 ) ( y - 5 ) ( y + 7 )}

\frac{1}{y ^{3} + 4 y ^{2} - 31 y - 70}

Solution steps

\frac{1}{( y + 2 ) ( y - 5 ) ( y + 7 )}

Expand

(y + 2) (y - 5) (y + 7) : y^{3} + 4 y^{2} - 31 y - 70

= \frac{1}{y ^{3} + 4 y ^{2} - 31 y - 70}

\frac{( x ^{2} + 5 ) ^{3}}{6}

\frac{1 + x}{( 2 x + 1 ) ( x - 1 )}

x d y \cdot (y + 3) - d y (y + 3)

\frac{d}{d t} ((s) (6 t^{5} - 8 t + 5))

(a, b) - 12 (a - b)^{2} + 7 (a - b) - 12

What is expand 1/((y+2)(y-5)(y+7)) ?
The solution to expand 1/((y+2)(y-5)(y+7)) is 1/(y^3+4y^2-31y-70)