What is expand (4(x-1)^2)/3 ?

The solution to expand (4(x-1)^2)/3 is (4x^2)/3-(8x)/3+4/3

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expand (4(x-1)^2)/3

expand

\frac{4 ( x - 1 ) ^{2}}{3}

\frac{4 x ^{2}}{3} - \frac{8 x}{3} + \frac{4}{3}

Solution steps

\frac{4 ( x - 1 ) ^{2}}{3}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{4 ( x ^{2} - 2 x + 1 )}{3}

Expand

4 (x^{2} - 2 x + 1) : 4 x^{2} - 8 x + 4

= \frac{4 x ^{2} - 8 x + 4}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 8 x + 4}{3} = \frac{4 x ^{2}}{3} - \frac{8 x}{3} + \frac{4}{3}

= \frac{4 x ^{2}}{3} - \frac{8 x}{3} + \frac{4}{3}

\frac{5 ( x + 1 )}{9 ( x + 3 )}

(\frac{d y}{d x} - 2 y) e^{2 x}

- \frac{2 ( - 2 x - 3 )}{x ^{4}}

h (t - 4) \cdot e^{t - 4}

(6 x + 4 z = 36) 2

What is expand (4(x-1)^2)/3 ?
The solution to expand (4(x-1)^2)/3 is (4x^2)/3-(8x)/3+4/3