What is expand e^x(acos(x)+bsin(x)) ?

The solution to expand e^x(acos(x)+bsin(x)) is ae^xcos(x)+be^xsin(x)

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expand e^x(acos(x)+bsin(x))

expand

e^{x} (a cos (x) + b sin (x))

a e^{x} cos (x) + b e^{x} sin (x)

Solution steps

e^{x} (a cos (x) + b sin (x))

Apply the distributive law:

a (b + c) = ab + a c

a = e^{x}, b = a cos (x), c = b sin (x)

= e^{x} a cos (x) + e^{x} b sin (x)

= a e^{x} cos (x) + b e^{x} sin (x)

n o t ab l es (2 - 5 x) (5 x + 2)

\frac{6 ( x + h ) + 5}{5 ( x + h ) - 6}

\frac{n ( n + 1 )}{6}

e^{2 p + 3} (3 p + 1)

\frac{2}{x ( x ^{2} + 2 )}

What is expand e^x(acos(x)+bsin(x)) ?
The solution to expand e^x(acos(x)+bsin(x)) is ae^xcos(x)+be^xsin(x)