What is expand ((10x+1)(10x-1))/(25) ?

The solution to expand ((10x+1)(10x-1))/(25) is 4x^2-1/25

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expand ((10x+1)(10x-1))/(25)

expand

\frac{( 10 x + 1 ) ( 10 x - 1 )}{25}

4 x^{2} - \frac{1}{25}

Solution steps

\frac{( 10 x + 1 ) ( 10 x - 1 )}{25}

Expand

(10 x + 1) (10 x - 1) : 100 x^{2} - 1

= \frac{100 x ^{2} - 1}{25}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{100 x ^{2} - 1}{25} = \frac{100 x ^{2}}{25} - \frac{1}{25}

= \frac{100 x ^{2}}{25} - \frac{1}{25}

Divide the numbers:

\frac{100}{25} = 4

= 4 x^{2} - \frac{1}{25}

\frac{- 2 x + 4}{( x - 1 ) ^{4}}

\frac{5 ( 1 - n )}{2}

(\cdot + 2 y + 3 z)^{2}

(5^{2})^{3}

(- \frac{x}{25 π} + 4)^{2}

What is expand ((10x+1)(10x-1))/(25) ?
The solution to expand ((10x+1)(10x-1))/(25) is 4x^2-1/25