What is expand (p+8)/((p+2)(p-1)) ?

The solution to expand (p+8)/((p+2)(p-1)) is (p+8)/(p^2+p-2)

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expand (p+8)/((p+2)(p-1))

expand

\frac{p + 8}{( p + 2 ) ( p - 1 )}

\frac{p + 8}{p ^{2} + p - 2}

Solution steps

\frac{p + 8}{( p + 2 ) ( p - 1 )}

Expand

(p + 2) (p - 1) : p^{2} + p - 2

= \frac{p + 8}{p ^{2} + p - 2}

(9 x^{2} - 28) e^{3}

(x + 3) (x +!)

(ln (0.5 x + 0.5) + 2.4)^{2}

(- 10, 2) y (- 5, - 1)

x (7 x - 248 = 5, y - 17) (2 y + 50 = x + 44)

What is expand (p+8)/((p+2)(p-1)) ?
The solution to expand (p+8)/((p+2)(p-1)) is (p+8)/(p^2+p-2)