What is expand ylog_{10}(xy)(1+ln(xy)) ?

The solution to expand ylog_{10}(xy)(1+ln(xy)) is ylog_{10}(yx)+yln(yx)log_{10}(yx)

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expand ylog_{10}(xy)(1+ln(xy))

expand

y lo g_{10} (x y) (1 + ln (x y))

y lo g_{10} (y x) + y ln (y x) lo g_{10} (y x)

Solution steps

y lo g_{10} (x y) (1 + ln (x y))

= y lo g_{10} (y x) (1 + ln (y x))

Apply the distributive law:

a (b + c) = ab + a c

a = y lo g_{10} (x y), b = 1, c = ln (x y)

= y lo g_{10} (x y) \cdot 1 + y lo g_{10} (x y) ln (x y)

= 1 \cdot y lo g_{10} (y x) + y ln (y x) lo g_{10} (y x)

Multiply:

1 \cdot y = y

= y lo g_{10} (y x) + y ln (y x) lo g_{10} (y x)

x + x + x + 2

(e^{x} + e^{- 2 x})^{2}

- 6 (2 w - 3 + 6 w = 6 + 2 (6 w - 1))

\frac{( b )}{s ^{2} ( s + a )}

(x + 6) \circ (2 - 2)^{2} - 1

What is expand ylog_{10}(xy)(1+ln(xy)) ?
The solution to expand ylog_{10}(xy)(1+ln(xy)) is ylog_{10}(yx)+yln(yx)log_{10}(yx)