What is expand (t-3)(s^2+4)^' ?

The solution to expand (t-3)(s^2+4)^' is t(s^2+4)^'-3(s^2+4)^'

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expand (t-3)(s^2+4)^'

expand

(t - 3) (s^{2} + 4)^{^{'}}

t (s^{2} + 4)^{'} - 3 (s^{2} + 4)^{'}

Solution steps

(t - 3) (s^{2} + 4)^{^{'}}

Apply the distributive law:

a (b - c) = ab - a c

a = (s^{2} + 4)^{^{'}}, b = t, c = 3

= (s^{2} + 4)^{^{^{'}}} t - (s^{2} + 4)^{^{^{'}}} \cdot 3

= t (s^{2} + 4)^{^{^{'}}} - 3 (s^{2} + 4)^{^{^{'}}}

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What is expand (t-3)(s^2+4)^' ?
The solution to expand (t-3)(s^2+4)^' is t(s^2+4)^'-3(s^2+4)^'