What is expand (3x+2)(7x-1)' ?

The solution to expand (3x+2)(7x-1)' is 3x(7x-1)'+2(7x-1)'

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expand (3x+2)(7x-1)'

expand

(3 x + 2) (7 x - 1)^{'}

3 x (7 x - 1)' + 2 (7 x - 1)'

Solution steps

(3 x + 2) (7 x - 1)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (7 x - 1)^{'}, b = 3 x, c = 2

= (7 x - 1)^{^{'}} 3 x + (7 x - 1)^{^{'}} 2

= 3 x (7 x - 1)^{^{'}} + 2 (7 x - 1)^{^{'}}

2 - 1

sin (2 (t + 2 π))

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1001 \cdot 34

\frac{1}{5 ( e ^{x} + 1 )}

What is expand (3x+2)(7x-1)' ?
The solution to expand (3x+2)(7x-1)' is 3x(7x-1)'+2(7x-1)'