What is expand (2x-7)/((3x+5)(9x-12)) ?

The solution to expand (2x-7)/((3x+5)(9x-12)) is (2x-7)/(27x^2+9x-60)

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expand (2x-7)/((3x+5)(9x-12))

expand

\frac{2 x - 7}{( 3 x + 5 ) ( 9 x - 12 )}

\frac{2 x - 7}{27 x ^{2} + 9 x - 60}

Solution steps

\frac{2 x - 7}{( 3 x + 5 ) ( 9 x - 12 )}

Expand

(3 x + 5) (9 x - 12) : 27 x^{2} + 9 x - 60

= \frac{2 x - 7}{27 x ^{2} + 9 x - 60}

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What is expand (2x-7)/((3x+5)(9x-12)) ?
The solution to expand (2x-7)/((3x+5)(9x-12)) is (2x-7)/(27x^2+9x-60)