What is expand u^1(u^2v^3,-u^3v^2) ?

The solution to expand u^1(u^2v^3,-u^3v^2) is u^2u^1v^3,-u^3u^1v^2

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expand u^1(u^2v^3,-u^3v^2)

expand

u^{1} (u^{2} v^{3}, - u^{3} v^{2})

u^{2} u^{1} v^{3}, - u^{3} u^{1} v^{2}

Solution steps

u^{1} (u^{2} v^{3}, - u^{3} v^{2})

= u^{1} (, u^{2} v^{3} - u^{3} v^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = u^{1}, b = u^{2} v^{3},, c = u^{3} v^{2}

= u^{1} u^{2} v^{3}, - u^{1} u^{3} v^{2}

= u^{2} u^{1} v^{3}, - u^{3} u^{1} v^{2}

2 (x + 2 = 6)

- 4 y (52 + 27)

4 + c

\frac{8 x ( x - 2 ) - 5}{x ( x - 2 ) + 1}

(x + 2) (x + 4)^{'}

What is expand u^1(u^2v^3,-u^3v^2) ?
The solution to expand u^1(u^2v^3,-u^3v^2) is u^2u^1v^3,-u^3u^1v^2