What is expand (7+x(2x+3))/(20) ?

The solution to expand (7+x(2x+3))/(20) is (x^2)/(10)+(3x)/(20)+7/20

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expand (7+x(2x+3))/(20)

expand

\frac{7 + x ( 2 x + 3 )}{20}

\frac{x ^{2}}{10} + \frac{3 x}{20} + \frac{7}{20}

Solution steps

\frac{7 + x ( 2 x + 3 )}{20}

Expand

7 + x (2 x + 3) : 7 + 2 x^{2} + 3 x

= \frac{7 + 2 x ^{2} + 3 x}{20}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{7 + 2 x ^{2} + 3 x}{20} = \frac{7}{20} + \frac{2 x ^{2}}{20} + \frac{3 x}{20}

= \frac{7}{20} + \frac{2 x ^{2}}{20} + \frac{3 x}{20}

Cancel

\frac{2 x ^{2}}{20} : \frac{x ^{2}}{10}

= \frac{7}{20} + \frac{x ^{2}}{10} + \frac{3 x}{20}

Rewrite in standard form

= \frac{x ^{2}}{10} + \frac{3 x}{20} + \frac{7}{20}

\frac{1}{( x + b ) ^{2}}

\frac{2 ( 5 + 223 )}{33}

\frac{a ( b - c ) ^{2}}{d}

(\frac{5}{9})^{5}

\frac{3 x ^{2} - 4 x - 1}{( x - 1 ) ^{3}}

What is expand (7+x(2x+3))/(20) ?
The solution to expand (7+x(2x+3))/(20) is (x^2)/(10)+(3x)/(20)+7/20