What are the solutions to the equation x^2-x+9=0 ?

The solutions to the equation x^2-x+9=0 are x= 1/2+i(sqrt(35))/2 ,x= 1/2-i(sqrt(35))/2

Find the zeros of x^2-x+9=0

The zeros of x^2-x+9=0 are x= 1/2+i(sqrt(35))/2 ,x= 1/2-i(sqrt(35))/2

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x^{2} - x + 9 = 0

x = \frac{1}{2} + i \frac{35}{2}, x = \frac{1}{2} - i \frac{35}{2}

Solution steps

x^{2} - x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 9 : 35 i

x_{1, 2} = \frac{- ( - 1 ) \pm 35 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 35 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 35 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 35 i}{2 \cdot 1} : \frac{1}{2} + i \frac{35}{2}

x = \frac{- ( - 1 ) - 35 i}{2 \cdot 1} : \frac{1}{2} - i \frac{35}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{35}{2}, x = \frac{1}{2} - i \frac{35}{2}

(\frac{14}{8})^{5}

- 3 \cdot \frac{1}{3}

∣ 2 x - 8 ∣ + 6 = 16

\frac{\frac{x ^{2} - y ^{2}}{x + y}}{\frac{x - y}{a}}

\frac{1}{3} p = \frac{1}{2} p + \frac{1}{3}

What are the solutions to the equation x^2-x+9=0 ?
The solutions to the equation x^2-x+9=0 are x= 1/2+i(sqrt(35))/2 ,x= 1/2-i(sqrt(35))/2
Find the zeros of x^2-x+9=0
The zeros of x^2-x+9=0 are x= 1/2+i(sqrt(35))/2 ,x= 1/2-i(sqrt(35))/2