What is expand ((3x+10)(x-6))/6 ?

The solution to expand ((3x+10)(x-6))/6 is (x^2)/2-(4x)/3-10

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expand ((3x+10)(x-6))/6

expand

\frac{( 3 x + 10 ) ( x - 6 )}{6}

\frac{x ^{2}}{2} - \frac{4 x}{3} - 10

Solution steps

\frac{( 3 x + 10 ) ( x - 6 )}{6}

Expand

(3 x + 10) (x - 6) : 3 x^{2} - 8 x - 60

= \frac{3 x ^{2} - 8 x - 60}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} - 8 x - 60}{6} = \frac{3 x ^{2}}{6} - \frac{8 x}{6} - \frac{60}{6}

= \frac{3 x ^{2}}{6} - \frac{8 x}{6} - \frac{60}{6}

Cancel

\frac{3 x ^{2}}{6} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2} - \frac{8 x}{6} - \frac{60}{6}

Cancel

\frac{8 x}{6} : \frac{4 x}{3}

= \frac{x ^{2}}{2} - \frac{4 x}{3} - \frac{60}{6}

Divide the numbers:

\frac{60}{6} = 10

= \frac{x ^{2}}{2} - \frac{4 x}{3} - 10

\frac{5 ( s + 2 )}{s ( s ^{2} + 8 s + 15 )}

\frac{8 - ( - 1 ) ^{x}}{x}

\frac{( x - 6 ) ( x - 9 )}{10}

(x^{3} - x^{2}) \cdot e^{x - 4}

t e^{a t} (cos (b t) + sin (b t))

What is expand ((3x+10)(x-6))/6 ?
The solution to expand ((3x+10)(x-6))/6 is (x^2)/2-(4x)/3-10