What is expand ((n+1)(n^3+1))/(n^4) ?

The solution to expand ((n+1)(n^3+1))/(n^4) is 1+1/(n^3)+1/n+1/(n^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((n+1)(n^3+1))/(n^4)

expand

\frac{( n + 1 ) ( n ^{3} + 1 )}{n ^{4}}

1 + \frac{1}{n ^{3}} + \frac{1}{n} + \frac{1}{n ^{4}}

Solution steps

\frac{( n + 1 ) ( n ^{3} + 1 )}{n ^{4}}

Expand

(n + 1) (n^{3} + 1) : n^{4} + n + n^{3} + 1

= \frac{n ^{4} + n + n ^{3} + 1}{n ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{4} + n + n ^{3} + 1}{n ^{4}} = \frac{n ^{4}}{n ^{4}} + \frac{n}{n ^{4}} + \frac{n ^{3}}{n ^{4}} + \frac{1}{n ^{4}}

= \frac{n ^{4}}{n ^{4}} + \frac{n}{n ^{4}} + \frac{n ^{3}}{n ^{4}} + \frac{1}{n ^{4}}

Apply rule

\frac{a}{a} = 1

\frac{n ^{4}}{n ^{4}} = 1

= 1 + \frac{n}{n ^{4}} + \frac{n ^{3}}{n ^{4}} + \frac{1}{n ^{4}}

Cancel

\frac{n}{n ^{4}} : \frac{1}{n ^{3}}

= 1 + \frac{1}{n ^{3}} + \frac{n ^{3}}{n ^{4}} + \frac{1}{n ^{4}}

Cancel

\frac{n ^{3}}{n ^{4}} : \frac{1}{n}

= 1 + \frac{1}{n ^{3}} + \frac{1}{n} + \frac{1}{n ^{4}}

\frac{4}{s ^{2} ( s + 1 ) ( s + 2 )}

5 (x^{2} + 5 = 6 x^{2})

π (108 y - 81 tan (y))

(x + 7) + (x + 2)

\frac{a z}{( 1 - b z ) ^{2}}

What is expand ((n+1)(n^3+1))/(n^4) ?
The solution to expand ((n+1)(n^3+1))/(n^4) is 1+1/(n^3)+1/n+1/(n^4)