What is expand 1-(1/2)^θ(1+θln(2)) ?

The solution to expand 1-(1/2)^θ(1+θln(2)) is 1-(1/2)^θ-ln(2)(1/2)^θθ

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expand 1-(1/2)^θ(1+θln(2))

expand

1 - (\frac{1}{2})^{θ} (1 + θ ln (2))

1 - (\frac{1}{2})^{θ} - ln (2) (\frac{1}{2})^{θ} θ

Solution steps

1 - (\frac{1}{2})^{θ} (1 + θ ln (2))

= 1 - (\frac{1}{2})^{θ} (1 + ln (2) θ)

Expand

- (\frac{1}{2})^{θ} (1 + θ ln (2)) : - (\frac{1}{2})^{θ} - ln (2) (\frac{1}{2})^{θ} θ

= 1 - (\frac{1}{2})^{θ} - ln (2) (\frac{1}{2})^{θ} θ

\frac{( a + b ) ^{2}}{a + b - 2}

x (\frac{p - x}{2})

, - x ((b + 1) (2 b + 1)) x - 2 b (b + 1)

\frac{3 ( x - 2 )}{4 ( x + 5 )}

\frac{( x - 5 ) ( x + 3 )}{x}

What is expand 1-(1/2)^θ(1+θln(2)) ?
The solution to expand 1-(1/2)^θ(1+θln(2)) is 1-(1/2)^θ-ln(2)(1/2)^θθ