What is expand ((1-4y)/3)^2 ?

The solution to expand ((1-4y)/3)^2 is (16y^2)/9-(8y)/9+1/9

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expand ((1-4y)/3)^2

expand

(\frac{1 - 4 y}{3})^{2}

\frac{16 y ^{2}}{9} - \frac{8 y}{9} + \frac{1}{9}

Solution steps

(\frac{1 - 4 y}{3})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 1 - 4 y ) ^{2}}{3 ^{2}}

(1 - 4 y)^{2} = 1 - 8 y + 16 y^{2}

= \frac{1 - 8 y + 16 y ^{2}}{3 ^{2}}

3^{2} = 9

= \frac{1 - 8 y + 16 y ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 8 y + 16 y ^{2}}{9} = \frac{1}{9} - \frac{8 y}{9} + \frac{16 y ^{2}}{9}

= \frac{1}{9} - \frac{8 y}{9} + \frac{16 y ^{2}}{9}

Rewrite in standard form

= \frac{16 y ^{2}}{9} - \frac{8 y}{9} + \frac{1}{9}

\frac{3 ( x + h ) ^{2} - 3 x}{h}

d y - (y - 8)^{2} d x

(x + 3) (x + 4 = 0)

\frac{9}{( 3 x - 1 ) ( 3 x + 5 )}

ln (x) (6 x + 1)

What is expand ((1-4y)/3)^2 ?
The solution to expand ((1-4y)/3)^2 is (16y^2)/9-(8y)/9+1/9