What is the d/(dt)((x)(b+c(t-2s)^2)) ?

The d/(dt)((x)(b+c(t-2s)^2)) is 2cx(t-2s)

What is the first d/(dt)((x)(b+c(t-2s)^2)) ?

The first d/(dt)((x)(b+c(t-2s)^2)) is 2cx(t-2s)

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\frac{d}{d t} ((x) (b + c (t - 2 s)^{2}))

2 c x (t - 2 s)

Solution steps

\frac{d}{d t} ((x) (b + c (t - 2 s)^{2}))

Treat

b, c, s, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d t} (b + c (t - 2 s)^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d b}{d t} + \frac{d}{d t} (c (t - 2 s)^{2}))

\frac{d b}{d t} = 0

\frac{d}{d t} (c (t - 2 s)^{2}) = 2 c (t - 2 s)

= x (0 + 2 c (t - 2 s))

Simplify

= 2 c x (t - 2 s)

\frac{( 25 - y ) ^{2}}{25}

5 (2 e + 6)

\frac{π w + s}{( 1 - π ) w - s}

\frac{x ^{2} + ( 1 + y ) ^{2}}{x y}

\frac{1}{N ( a - b N )}

What is the d/(dt)((x)(b+c(t-2s)^2)) ?
The d/(dt)((x)(b+c(t-2s)^2)) is 2cx(t-2s)
What is the first d/(dt)((x)(b+c(t-2s)^2)) ?
The first d/(dt)((x)(b+c(t-2s)^2)) is 2cx(t-2s)