What is expand (4x-1)/(2(4x+1)) ?

The solution to expand (4x-1)/(2(4x+1)) is (4x-1)/(8x+2)

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expand (4x-1)/(2(4x+1))

expand

\frac{4 x - 1}{2 ( 4 x + 1 )}

\frac{4 x - 1}{8 x + 2}

Solution steps

\frac{4 x - 1}{2 ( 4 x + 1 )}

Expand

2 (4 x + 1) : 8 x + 2

= \frac{4 x - 1}{8 x + 2}

tan (2 (x + \frac{π}{6}))

\frac{x}{( x - 0.6 ) ( x + 0.5 ) ^{2}}

(e^{- i w} - 1)^{2} (e^{i w} - 1)^{2}

\frac{1}{x ^{3} ( x + 1 ) ^{2}}

8 n - 6 (- 5 n - 3 = 18 + 7 n)

What is expand (4x-1)/(2(4x+1)) ?
The solution to expand (4x-1)/(2(4x+1)) is (4x-1)/(8x+2)