What is expand ((2x+3)(x-1))/2 ?

The solution to expand ((2x+3)(x-1))/2 is x^2+x/2-3/2

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expand ((2x+3)(x-1))/2

expand

\frac{( 2 x + 3 ) ( x - 1 )}{2}

x^{2} + \frac{x}{2} - \frac{3}{2}

Solution steps

\frac{( 2 x + 3 ) ( x - 1 )}{2}

Expand

(2 x + 3) (x - 1) : 2 x^{2} + x - 3

= \frac{2 x ^{2} + x - 3}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + x - 3}{2} = \frac{2 x ^{2}}{2} + \frac{x}{2} - \frac{3}{2}

= \frac{2 x ^{2}}{2} + \frac{x}{2} - \frac{3}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{2} + \frac{x}{2} - \frac{3}{2}

\frac{( 6 + x ^{2} + 5 x ) ^{2}}{( a + 2 )}

(3 c - 4 e) 2 (- 3 c - 4 d)

- \frac{1000}{( s - 1 ) ( s + 1 ) ( s + 20 )}

\frac{2}{s ( s ^{2} + 4 s )}

(3.6 \cdot t^{'} + 15)^{2}

What is expand ((2x+3)(x-1))/2 ?
The solution to expand ((2x+3)(x-1))/2 is x^2+x/2-3/2