What is expand ((1+k^2)i)/(1+ki)+(k-6i) ?

The solution to expand ((1+k^2)i)/(1+ki)+(k-6i) is (i+k^2i)/(1+ki)+k-6i

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expand ((1+k^2)i)/(1+ki)+(k-6i)

expand

\frac{( 1 + k ^{2} ) i}{1 + ki} + (k - 6 i)

\frac{i + k ^{2} i}{1 + ki} + k - 6 i

Solution steps

\frac{( 1 + k ^{2} ) i}{1 + ki} + (k - 6 i)

Remove parentheses:

(a) = a

= \frac{( 1 + k ^{2} ) i}{1 + ki} + k - 6 i

Expand

(1 + k^{2}) i : i + k^{2} i

= \frac{i + k ^{2} i}{ki + 1} + k - 6 i

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(4 - 3 cos^{2} (x)) sin (x) d x

, (x - 2 y + 2 z)

\frac{( ( x + 4 ) ( x + 1 ) ( x - 2 ) )}{4}

\frac{1}{s ( 2000 - s )}

What is expand ((1+k^2)i)/(1+ki)+(k-6i) ?
The solution to expand ((1+k^2)i)/(1+ki)+(k-6i) is (i+k^2i)/(1+ki)+k-6i