What is expand (19x+12)/(x(x+1)(x+2)) ?

The solution to expand (19x+12)/(x(x+1)(x+2)) is (19x+12)/(x^3+3x^2+2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (19x+12)/(x(x+1)(x+2))

expand

\frac{19 x + 12}{x ( x + 1 ) ( x + 2 )}

\frac{19 x + 12}{x ^{3} + 3 x ^{2} + 2 x}

Solution steps

\frac{19 x + 12}{x ( x + 1 ) ( x + 2 )}

Expand

x (x + 1) (x + 2) : x^{3} + 3 x^{2} + 2 x

= \frac{19 x + 12}{x ^{3} + 3 x ^{2} + 2 x}

\frac{2 n + 4}{( 2 n + 1 ) ( 2 n + 3 )}

(1 - 3 i)^{13}

e^{(- 0.0833 + 0.1729 i) \cdot 2}

\frac{16}{s ^{2} ( s ^{2} + 4 )}

\frac{( x - 3 )}{( x - 1 ) ( x + 1 )}

What is expand (19x+12)/(x(x+1)(x+2)) ?
The solution to expand (19x+12)/(x(x+1)(x+2)) is (19x+12)/(x^3+3x^2+2x)