What are the solutions to the equation (x-4)(x+5)=0 ?

The solutions to the equation (x-4)(x+5)=0 are x=4,x=-5

Find the zeros of (x-4)(x+5)=0

The zeros of (x-4)(x+5)=0 are x=4,x=-5

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(x - 4) (x + 5) = 0

x = 4, x = - 5

Solution steps

(x - 4) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

\frac{1}{2} \cdot 8 \cdot 10

\frac{64}{9}

\frac{( 6.63 \cdot 1 0 ^{- 34} ) ( 3 \cdot 1 0 ^{8} )}{4.86 \cdot 1 0 ^{- 7}}

3 (x + 8)^{2} + 8 = 83

\frac{x ^{\frac{3}{7}}}{x ^{\frac{3}{14}}}

What are the solutions to the equation (x-4)(x+5)=0 ?
The solutions to the equation (x-4)(x+5)=0 are x=4,x=-5
Find the zeros of (x-4)(x+5)=0
The zeros of (x-4)(x+5)=0 are x=4,x=-5