What is expand (2t+3)*(ln(2t-3)) ?

The solution to expand (2t+3)*(ln(2t-3)) is 2tln(2t-3)+3ln(2t-3)

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expand (2t+3)*(ln(2t-3))

expand

(2 t + 3) \cdot (ln (2 t - 3))

2 t ln (2 t - 3) + 3 ln (2 t - 3)

Solution steps

(2 t + 3) (ln (2 t - 3))

= (ln (2 t - 3)) (2 t + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = (ln (2 t - 3)), b = 2 t, c = 3

= (ln (2 t - 3)) \cdot 2 t + (ln (2 t - 3)) \cdot 3

= 2 t (ln (2 t - 3)) + 3 (ln (2 t - 3))

Remove parentheses:

(a) = a

= 2 t ln (2 t - 3) + 3 ln (2 t - 3)

4 (x - 1) - 2 (3 x + 5 = - 3 x - 1)

e^{P} (P + P P)

\frac{( x ^{2} - 1 )}{( x - 4 ) \cdot 5}

(w + 7) (w + 3)^{'}

\frac{6 ( 7 x + 6 )}{( x + 6 ) ( x - 6 )}

What is expand (2t+3)*(ln(2t-3)) ?
The solution to expand (2t+3)*(ln(2t-3)) is 2tln(2t-3)+3ln(2t-3)