What is expand y(y^2-2y=x^2-x+c) ?

The solution to expand y(y^2-2y=x^2-x+c) is y^3-2y^2=x^2-xy+cy(x)

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expand y(y^2-2y=x^2-x+c)

expand

y (y^{2} - 2 y = x^{2} - x + c)

y^{3} - 2 y^{2} = x^{2} - x y + cy (x)

Solution steps

y (y^{2} - 2 y = x^{2} - x + c)

= y (y^{2} - 2 = x^{2} y - x + c)

Distribute parentheses

= y y^{2} + y (- 2 y = x^{2}) + y (- x) + yc

Apply minus-plus rules

+ (- a) = - a

y y^{2} - 2 yy = x^{2} - x y + cy (x)

Expand

y y^{2} - 2 yy : y^{3} - 2 y^{2}

y^{3} - 2 y^{2} = x^{2} - x y + cy (x)

(u^{2} y^{2} - y^{2}) (u d y + y d u)

(- 4) (- 3) (2) (- 5)

t^{2} \cdot d i r a c (t - π)

(y^{3} + (- x) y^{2}) d x + 2 x^{2} y d y

\frac{d}{d t} ((X) ((X - 1) (1 - 2 X)))

What is expand y(y^2-2y=x^2-x+c) ?
The solution to expand y(y^2-2y=x^2-x+c) is y^3-2y^2=x^2-xy+cy(x)