What is expand (3(k+2)(k-3))/5 ?

The solution to expand (3(k+2)(k-3))/5 is (3k^2)/5-(3k)/5-18/5

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expand (3(k+2)(k-3))/5

expand

\frac{3 ( k + 2 ) ( k - 3 )}{5}

\frac{3 k ^{2}}{5} - \frac{3 k}{5} - \frac{18}{5}

Solution steps

\frac{3 ( k + 2 ) ( k - 3 )}{5}

Expand

3 (k + 2) (k - 3) : 3 k^{2} - 3 k - 18

= \frac{3 k ^{2} - 3 k - 18}{5}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 k ^{2} - 3 k - 18}{5} = \frac{3 k ^{2}}{5} - \frac{3 k}{5} - \frac{18}{5}

= \frac{3 k ^{2}}{5} - \frac{3 k}{5} - \frac{18}{5}

(t - e^{2 t}) \cdot (- (3 + 2 e^{2 t}))

(1 - t) sin (π t) (1 - 2 t)

\frac{d}{d y} ((x) (x + 2 x y))

\frac{( x - 1 ) ( x - 5 )}{( x - 2 ) ( x - 4 )}

\frac{( 4 k - 7 ) ^{2}}{9}

What is expand (3(k+2)(k-3))/5 ?
The solution to expand (3(k+2)(k-3))/5 is (3k^2)/5-(3k)/5-18/5