What is expand (2-t)(1-e^{1-t}) ?

The solution to expand (2-t)(1-e^{1-t}) is 2-2e^{1-t}-t+e^{1-t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2-t)(1-e^{1-t})

expand

(2 - t) (1 - e^{1 - t})

2 - 2 e^{1 - t} - t + e^{1 - t} t

Solution steps

(2 - t) (1 - e^{1 - t})

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2, b = - t, c = 1, d = - e^{1 - t}

= 2 \cdot 1 + 2 (- e^{1 - t}) + (- t) \cdot 1 + (- t) (- e^{1 - t})

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 2 \cdot 1 - 2 e^{1 - t} - 1 \cdot t + e^{1 - t} t

Simplify

2 \cdot 1 - 2 e^{1 - t} - 1 \cdot t + e^{1 - t} t : 2 - 2 e^{1 - t} - t + e^{1 - t} t

= 2 - 2 e^{1 - t} - t + e^{1 - t} t

\frac{x y ( x + y )}{( x ^{2} + y ^{2} )}

e x^{2} + (e + 1) x + 1

4 x (y^{1} f (x, y, O) + 2 x y^{1} - y = O)

\frac{g ( x + h ) - 4}{g ( x + h ) + 5}

\frac{2}{x ( x + 3 )}

What is expand (2-t)(1-e^{1-t}) ?
The solution to expand (2-t)(1-e^{1-t}) is 2-2e^{1-t}-t+e^{1-t}t