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Popular >

expand (y+1)(y-1)'

Solution

expand

(y + 1) (y - 1)^{'}

Solution

(y - 1)' y + (y - 1)'

Solution steps

(y + 1) (y - 1)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (y - 1)^{'}, b = y, c = 1

= (y - 1)^{^{'}} y + (y - 1)^{^{'}} 1

= (y - 1)^{^{'}} y + 1 (y - 1)^{^{'}}

Multiply:

1 (y - 1)^{'} = (y - 1)^{'}

= (y - 1)^{^{'}} y + (y - 1)^{^{'}}

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Frequently Asked Questions (FAQ)

What is expand (y+1)(y-1)' ?
The solution to expand (y+1)(y-1)' is (y-1)'y+(y-1)'