What is expand ,2y^2x-y^2-(1+3y) ?

The solution to expand ,2y^2x-y^2-(1+3y) is 2y^2x-y^2-1-3y

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expand ,2y^2x-y^2-(1+3y)

expand

2 y^{2} x - y^{2} - (1 + 3 y)

2 y^{2} x - y^{2} - 1 - 3 y

Solution steps

2 y^{2} x - y^{2} - (1 + 3 y)

Apply the distributive law:

- (a + b) = - a - b

- (1 + 3 y) = - 1 - 3 y

= 2 y^{2} x - y^{2} - 1 - 3 y

sec (2 x - 3 0^{\circ})

\frac{1}{x ( x ^{2} + y ^{2} )}

\frac{6 x}{( 1 - 3 x ^{2} ) ^{2}}

\frac{3 ( 2 x - 5 y )}{5 x - 2 y}

e^{x} \cdot (e^{z + 1} - 1)

What is expand ,2y^2x-y^2-(1+3y) ?
The solution to expand ,2y^2x-y^2-(1+3y) is 2y^2x-y^2-1-3y