What is expand (3f+2g=5,)(f-g=1) ?

The solution to expand (3f+2g=5,)(f-g=1) is 3f^2-3gf=1

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expand (3f+2g=5,)(f-g=1)

expand

(3 f + 2 g = 5,) (f - g = 1)

3 f^{2} - 3 g f = 1

Solution steps

(3 f + 2 g = 5,) (f - g = 1)

= (3 f + 2 \cdot 5 =, g) (f - 1 = g)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 3 f, b = 2 g = 5,, c = f, d = - g = 1

3 ff + 3 f (- g = 1) + 2 g = 5, f + 2 g = 5, (- g = 1)

Apply minus-plus rules

+ (- a) = - a

3 ff - 3 g f = 1 + 2 g = 5, f - 2 g = 5, g = 1

Expand

3 ff - 3 g f : 3 f^{2} - 3 g f

3 f^{2} - 3 g f = 1

(4 x - 5, x^{2} + 4) (x)

\frac{( x - 1 ) e ^{2 x}}{2}

- 4 b (- 2 b e^{2} - 4)

\frac{3}{( x + 5 ) ^{3}}

\frac{1}{( 2 x + 1 ) ^{3}}

What is expand (3f+2g=5,)(f-g=1) ?
The solution to expand (3f+2g=5,)(f-g=1) is 3f^2-3gf=1