What is expand 3/2-3(-1) ?

The solution to expand 3/2-3(-1) is 9/2

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expand 3/2-3(-1)

expand

\frac{3}{2} - 3 (- 1)

\frac{9}{2}

Decimal

4.5

Solution steps

\frac{3}{2} - 3 (- 1)

Apply rule

- (- a) = a

= \frac{3}{2} + 3 \cdot 1

Multiply the numbers:

3 \cdot 1 = 3

= \frac{3}{2} + 3

Convert element to fraction:

3 = \frac{3 \cdot 2}{2}

= \frac{3 \cdot 2}{2} + \frac{3}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 2 + 3}{2}

3 \cdot 2 + 3 = 9

= \frac{9}{2}

\frac{( x ^{3} + 1 ) d x}{x ^{2}}

\frac{d}{d y} ((x) (x^{2} + x))

(sin (y) - y sin (x)) d y

e^{2 x} (y - 2)

- 2 (4 x ln (x) + 2 x)