What is expand (k(9-k))/2+(6-k) ?

The solution to expand (k(9-k))/2+(6-k) is (9k)/2-(k^2)/2+6-k

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (k(9-k))/2+(6-k)

expand

\frac{k ( 9 - k )}{2} + (6 - k)

\frac{9 k}{2} - \frac{k ^{2}}{2} + 6 - k

Solution steps

\frac{k ( 9 - k )}{2} + (6 - k)

Remove parentheses:

(a) = a

= \frac{k ( 9 - k )}{2} + 6 - k

Expand

k (9 - k) : 9 k - k^{2}

= \frac{- k ^{2} + 9 k}{2} + 6 - k

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 k - k ^{2}}{2} = \frac{9 k}{2} - \frac{k ^{2}}{2}

= \frac{9 k}{2} - \frac{k ^{2}}{2} + 6 - k

(x + y)^{2} + 8

\frac{( - 19 - 3 y ) ^{2}}{2}

(7 x - 4) \cdot (8 x + 5)^{'}

((8 + h)^{'})^{3}

\frac{26 x - 12 h + 12}{3 ( 2 x + 3 )}

What is expand (k(9-k))/2+(6-k) ?
The solution to expand (k(9-k))/2+(6-k) is (9k)/2-(k^2)/2+6-k