What is expand 3(n-1=5n+3-2n) ?

The solution to expand 3(n-1=5n+3-2n) is 3n-3=-n+9

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expand 3(n-1=5n+3-2n)

expand

3 (n - 1 = 5 n + 3 - 2 n)

3 n - 3 = - n + 9

Solution steps

3 (n - 1 = 5 n + 3 - 2 n)

= 3 (n - 1 \cdot 5 = n + 3 - 2 n)

Distribute parentheses

= 3 n + 3 (- 1 = 5 n) + 3 \cdot 3 + 3 (- 2 n)

Apply minus-plus rules

+ (- a) = - a

3 n - 3 \cdot 1 = 5 n + 3 \cdot 3 - 3 \cdot 2 n

Simplify

3 n - 3 \cdot 1 = 5 n + 3 \cdot 3 - 3 \cdot 2 n : 3 n - 3 = - n + 9

3 n - 3 = - n + 9

\frac{1}{( 5 x - 2 ) ^{2}}

\frac{( x - 3 ) ( x + 1 )}{( x + 2 )}

cos (\frac{π}{2} (1 - a))

C (500 = 8000 + C)

\frac{x ^{3} - 8}{x - 2}

What is expand 3(n-1=5n+3-2n) ?
The solution to expand 3(n-1=5n+3-2n) is 3n-3=-n+9