What are the solutions to the equation x^2+12x+34=0 ?

The solutions to the equation x^2+12x+34=0 are x=-6+sqrt(2),x=-6-sqrt(2)

Find the zeros of x^2+12x+34=0

The zeros of x^2+12x+34=0 are x=-6+sqrt(2),x=-6-sqrt(2)

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x^{2} + 12 x + 34 = 0

x = - 6 + 2, x = - 6 - 2

Decimal Notation

x = - 4.58578 \dots, x = - 7.41421 \dots

Solution steps

x^{2} + 12 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 34 = 22

x_{1, 2} = \frac{- 12 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 2}{2 \cdot 1}

x = \frac{- 12 + 2 2}{2 \cdot 1} : - 6 + 2

x = \frac{- 12 - 2 2}{2 \cdot 1} : - 6 - 2

The solutions to the quadratic equation are:

x = - 6 + 2, x = - 6 - 2

\frac{3}{4} (- 1)^{\frac{4}{3}}

∣ 2 x - 8 ∣ \geq 3

\frac{3 u ^{3} v ^{4} - 2 u ^{5} v ^{2} + ( u ^{2} v ^{2} ) ^{2}}{u ^{3} v ^{2}}

- 40 = 4 x + 20 + x

a^{2} + 28 a + 27

What are the solutions to the equation x^2+12x+34=0 ?
The solutions to the equation x^2+12x+34=0 are x=-6+sqrt(2),x=-6-sqrt(2)
Find the zeros of x^2+12x+34=0
The zeros of x^2+12x+34=0 are x=-6+sqrt(2),x=-6-sqrt(2)