What is expand-3(-4a-3b-5c=2) ?

The solution to expand-3(-4a-3b-5c=2) is 12a+9b+15c=2

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expand-3(-4a-3b-5c=2)

expand

- 3 (- 4 a - 3 b - 5 c = 2)

12 a + 9 b + 15 c = 2

Solution steps

- 3 (- 4 a - 3 b - 5 c = 2)

= - 3 (- 4 a - 3 b - 5 \cdot 2 = c)

Distribute parentheses

= (- 3) (- 4 a) + (- 3) (- 3 b) + (- 3) (- 5 c = 2)

Apply minus-plus rules

(- a) (- b) = ab

3 \cdot 4 a + 3 \cdot 3 b + 3 \cdot 5 c = 2

Expand

3 \cdot 4 a + 3 \cdot 3 b + 3 \cdot 5 c : 12 a + 9 b + 15 c

12 a + 9 b + 15 c = 2

\frac{1}{( x ^{3} + 7 ) ^{6}}

\frac{5 y ^{2} - 6 y - 5}{5 y ( 5 y - 3 )}

\frac{5 ( 5 - 17 )}{2}

h^{'} (t) (- 16 t^{2} + 46 t + 151)

(a^{'} 2 + 5 a + 4)^{2}

What is expand-3(-4a-3b-5c=2) ?
The solution to expand-3(-4a-3b-5c=2) is 12a+9b+15c=2