What is expand 8sin(t)h(pi-t) ?

The solution to expand 8sin(t)h(pi-t) is 8pihsin(t)-8htsin(t)

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expand 8sin(t)h(pi-t)

expand

8 sin (t) h (π - t)

8 πh sin (t) - 8 h t sin (t)

Solution steps

8 sin (t) h (π - t)

= 8 h sin (t) (π - t)

Apply the distributive law:

a (b - c) = ab - a c

a = 8 sin (t) h, b = π, c = t

= 8 sin (t) hπ - 8 sin (t) h t

= 8 πh sin (t) - 8 h t sin (t)

2 (\frac{3}{2} a + b = 1)

2 x + 1 (x^{2} + 7)

(1.4) (y = 3 x + 1)

\frac{x ^{2} - 2 x + 4}{( x - 1 ) ^{2}}

(2 y^{2} x - 3) d x + (k y x^{2} + 4) d y

What is expand 8sin(t)h(pi-t) ?
The solution to expand 8sin(t)h(pi-t) is 8pihsin(t)-8htsin(t)