What is expand 2/(e^{u(t-1)^2)} ?

The solution to expand 2/(e^{u(t-1)^2)} is 2/(e^{ut^2-2ut+u)}

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expand 2/(e^{u(t-1)^2)}

expand

\frac{2}{e ^{u (t - 1)^{2}}}

\frac{2}{e ^{u t^{2} - 2 u t + u}}

Solution steps

\frac{2}{e ^{u (t - 1)^{2}}}

e^{u (t - 1)^{2}} = e^{u t^{2} - 2 u t + u}

= \frac{2}{e ^{u t^{2} - 2 u t + u}}

\frac{( ( 1 + 3 x ) ^{3} )}{3 - x}

\frac{( n ) ( n + 1 )}{2}

A (1, - 5) B (- 2, 4)

(1 - e^{- t} - t \cdot e^{- t}) u (t)

\frac{x ^{2} + 6 x + 13}{2 ( x + 3 )}

What is expand 2/(e^{u(t-1)^2)} ?
The solution to expand 2/(e^{u(t-1)^2)} is 2/(e^{ut^2-2ut+u)}