What are the solutions to the equation 9x^2-18x=0 ?

The solutions to the equation 9x^2-18x=0 are x=2,x=0

Find the zeros of 9x^2-18x=0

The zeros of 9x^2-18x=0 are x=2,x=0

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9 x^{2} - 18 x = 0

x = 2, x = 0

Solution steps

9 x^{2} - 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 0 = 18

x_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 18}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 18}{2 \cdot 9}

x = \frac{- ( - 18 ) + 18}{2 \cdot 9} : 2

x = \frac{- ( - 18 ) - 18}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

ln (3 x)

(46 t - 16 t^{2}) - 28

1.5 \times 1 0^{- 5}

a^{2} + 5 a - 6

d^{2} - 7 d + 10

What are the solutions to the equation 9x^2-18x=0 ?
The solutions to the equation 9x^2-18x=0 are x=2,x=0
Find the zeros of 9x^2-18x=0
The zeros of 9x^2-18x=0 are x=2,x=0