What is expand x^{\circ-1}(x+2) ?

The solution to expand x^{\circ-1}(x+2) is xx^{\circ-1}+2x^{\circ-1}

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expand x^{\circ-1}(x+2)

expand

x^{\circ - 1} (x + 2)

x x^{\circ- 1} + 2 x^{\circ- 1}

Solution steps

x^{\circ - 1} (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = x^{\circ - 1}, b = x, c = 2

= x^{\circ - 1} x + x^{\circ - 1} \cdot 2

= x x^{\circ - 1} + 2 x^{\circ - 1}

- \frac{( 10 - x ) ^{4}}{25}

\frac{d}{d y} ((x) (y - p (x) x))

(2 + \frac{y}{x ^{2}}) d y

\frac{14 x ^{3}}{( x - 3 ) ^{2}}

\frac{( x + 1 ) ( x + 2 )}{( x - 2 ) ( x - 1 )}

What is expand x^{\circ-1}(x+2) ?
The solution to expand x^{\circ-1}(x+2) is xx^{\circ-1}+2x^{\circ-1}