What is expand 2(x+1)ln(x+1) ?

The solution to expand 2(x+1)ln(x+1) is 2xln(x+1)+2ln(x+1)

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expand 2(x+1)ln(x+1)

expand

2 (x + 1) ln (x + 1)

2 x ln (x + 1) + 2 ln (x + 1)

Solution steps

2 (x + 1) ln (x + 1)

= 2 ln (x + 1) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = 2 ln (x + 1), b = x, c = 1

= 2 ln (x + 1) x + 2 ln (x + 1) \cdot 1

= 2 x ln (x + 1) + 2 \cdot 1 \cdot ln (x + 1)

Multiply the numbers:

2 \cdot 1 = 2

= 2 x ln (x + 1) + 2 ln (x + 1)

(1 + 2 i ∣)^{2}

(- 4, - 5) y (1, 3)

\frac{( 8 + ( - 1 ) ^{n} )}{n}

\frac{2 x ^{3} ( x + 4 ) ^{3}}{x + 2}

- \frac{14}{( x + 1 ) ^{3}}

What is expand 2(x+1)ln(x+1) ?
The solution to expand 2(x+1)ln(x+1) is 2xln(x+1)+2ln(x+1)